56. a gas has an initial volume of 2.50 l and
temperature of 45 °c. what is the temperature if
the volume is changed to 1.80 l?

T₂ =  228.96 k

Explanation:

Given data;

Initial volume = 2.50 L

Initial temperature = 45°C

Final volume = 1.80 L

Final temperature = ?

Solution;

( 45+273 = 318 K)

According to charle's law,

V₁/T₁ = V₂/T₂

T₂  = V₂T₁ /V₁

T₂ = 1.80 L× 318 K/ 2.50 L

T₂ = 572.4 L. K / 2.50 L

T₂ =  228.96 k

the answer is 75.0%.