Calculate the number of grams of carbon dioxide produced from complete combustion of one liter of octane by placing the conversions in the correct order. make sure the units of adjacent conversion factors cancel out. 1 l octane times times times times times = 2171 g carbon dioxide

15.71g

Explanation:

The general combustion equation for all hydrocarbons is

CxHy + (x+y/4) O2 = xCO2 + (y/2) H2O

For octane, C8H18 :

C8H18 + ( 8 + 18/4 ) O2 = 8CO2 + 9H2O

C8H18 + 50/4 O2 = 8CO2 + 9H2O

C8H18 + 25/2 O2 = 8CO2 + 9H2O

2C8H18 + 25 O2 = 16 CO2 + 18H2O (balanced)

From the balanced equation,

2 x 22.4 L of octane produced 16 [ 12 + (16 x 2)] of carbon dioxide

That is,

44.8 L of octane produced 704g of carbon dioxide

So, 1L of octane will produce 1 L x 704g/44.8 L = 15.71g of carbon dioxide

Therefore, 15.71g of carbon dioxide will be produced by the complete combustion of 1 L of octane.

a. energy is absorbed in the reaction.

if in a given reaction the energy of products is greater than the energy of reactants it means that reaction is endothermic and during the reaction, the energy is absorbed by reactants. in an endothermic reaction, the products have more stored chemical energy than the reactants. and in this reaction the reactants are more stable than products before the compounds with less energy are always more stable.