Potassium chlorate (used in fireworks, flares, and safety matches) forms oxygen and potassium chloride when heated. kclo3(s) → kcl(s) + o2(g) [unbalanced] how many grams of oxygen are formed when 26.4 g of potassium chlorate is heated?

10.3 g of oxygen are formed when 26.4 g of potassium chlorate is heated

Explanation:

This is the balanced equation:

2KClO₃(s) → 2KCl(s) + 3O₂(g)

Ratio beteween the salt and oxygen is 2:3

Molar mass of KClO₃ = 122.55 g/m

Let's find out the moles of salt

Mass / Molar mass

26.4 g /122.55 g/m = 0.215 moles

So, this is the final rule of three:

If 2 moles of KClO₃ make 3 moles of oxygen

0.215 moles of KClO₃ make  (0.215  .3) /2 = 0.323 moles of O₂ are produced

Molar mass O₂ = 32 g/m

Moles . molar mass = mass

0.323 m  . 32g/m = 10.3 g

your answer would be a. 12.5 kg

dynamic equilibrium is the answer.