A12.0 wt% solution of cacl2 (110.98 g/mol) has a density of 1.107 g/ml.

a) what is the mass (in milligrams) of a 15.0-ml solution of 12.0 wt% cacl2?

b) what is the mass (in grams) of cacl2 in 431.3 ml of a 12.0 wt% solution of cacl2?

c) what is the formal concentration of cacl2 (in molarity) of the 431.3-ml cacl2 solution described in part b?

a) Mass of solution is 16,605 milli grams.

b) 57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) 1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

Explanation:

Mass by mass percentage of calcium chloride solution, wt% = 12.0%

Density of the solution = d = 1.107 g/mL

a) Volume of the solution , V= 15.0 mL

Mass of the solution = m

Mass of solution = 16.605 g = 16,605 mg (1g = 1000 mg)

b) Mass of the solution = m

Volume of the solution = V = 431.3 mL

Mass of calcium chloride = x

w% = 12.0%

57.29 grams is the mass of calcium chloride in 431.3 mL of a 12.0 wt% solution.

c) Moles of calcium chloride =

V = Volume of the solution in Liters

n = 0.5161 mole

V = 431.3 mL = 0.4313 L

1.1967 mol/L is the formal concentration of calcium chloride in 431.3 mL solution.

answer: at room temperature (roughly 20 degrees c), you can dissolve 203.9 grams (or 200 grams) of sugar in 100 ml of water. as water temperature increases, the amount of sugar that will dissolve increases, up to about 500 grams of sugar in 100 ml water at 100 degrees c.

explanation: