Consider a solution containing 3.54 mm of an analyte, x, and 1.23 mm of a standard, s. upon chromatographic separation of the solution peak areas for x and s are 3275 and 10829, respectively. determine the response factor for x relative to s. f=to determine the concentration of x in an unknown solution, 1.00 ml of 8.27 mm s was added to 5.00 ml of the unknown x solution and the mixture was diluted to 10.0 ml. after chromatographic separation, this solution gave peak areas of 5389 and 4627 for x and s, respectively. determine the concentration of s in the 10.0 ml solution.[s]=determine the concentration of x in the 10.0 ml solution.[x]=determine the concentration of x in the unknown solution.[x]=

The response factor for X relative to S is 0,105

Concentration of X in the unknown solution is: 18,3mM

Explanation:

The response factor of X is:

RF x = peak area / concentration = 925

And of S:

RF s = 10829 / 1,23 = 8804

The response factor for X relative to S is:

RRF = 925/8804 = 0,105

Concentration of S in the unknown solution is:

8,27mM× = 0,827mM

-Because the 1,00 mL of S was diluted from 1,00mL to 10,0mL-

Using the RRF formula:

Conc X = Peak area X* Concentration B / peak area S * RRF

[X] = 5389*0,827mM / 4627*0,105

[X] = 9,17mM in the 10,0mL solution.

In the unknown solution:

9,17mM× = 18,3mM

I hope it helps!

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest

i would say b

explanation:

but i think i would need more information than that