Light with a wavelength of 614.5 nm looks orange. what is the energy, in joules, per photon of this orange light? what is the energy in ev (1 ev = 1.602 × 10−19 j)?

The energy is 2.00eV

Explanation:

From Planck's theory

E=hf = hc/k

Where h is the planck constant =

6.6×10^-34m2kg/s

C= speed of light =3.0 ×10^8m/s

k= wavelength = 651.4nm=651.4 ×10^-9

E=(6.6×10^-34 × 3.0 ×10^8)/(651.4×10^-9)

E=3.22 × 10^-19J

1eV = 1.602×10^-19J

E=2.00eV

The energy is 2.00eV

vanderwaal's forces of attraction are the electrostatic intermolecular forces that exist in a molecule due to the temporary or permanent dipoles that are developed in a molecule. in , the major intermolecular forces are dipole-dipole interactions as the molecule is polar (bent structure). so the vanderwaal's forces of interaction in between molecules are the permanent dipole-dipole interactions that develop due to the dipole that exists in between the polar h - s bond. the positively charged hydrogen atom is attracted towards the negative end of the dipole that is sulfur of the adjacent molecule. therefore, these forces of attraction are relatively stronger than that of london dispersion forces that exist in non polar molecules.