How many grams of c₆h₆ must decompose according to the following chemical equation to transfer 430kj of heat?
c₆h₆(l) → 3 c₂h₂(g)∆h= 630 kj

53.3 g C6H6

Explanation:

                              C₆H₆(l) → 3 C₂H₂(g)        ∆H= 630 kj

From reaction       1 mol                                ∆H= 630 kj

Given                     x mol                                ∆H= 430 kj

x = (1 mol*430 kJ)/630 kJ = 0.683 mol  C6H6

M(C6H6) = 12*6 + 1*6= 78 g/mol

0.683 mol  C6H6 * 78 g/mol ≈ 53.3 g

53.24 g of C₆H₆ will decompose to transfer 430 KJ of heat energy

The balanced equation for the reaction is given below:

Next, we shall determine the mass of C₆H₆ that decomposed to transfer 630 KJ of heat energy.

Molar mass of C₆H₆ = (12×6) + (1×6)

= 72 + 6

= 78 g/mol

Mass of C₆H₆ from the balanced equation = 1 × 78 = 78 g

Thus,

From the balanced equation above,

78 g of C₆H₆ decomposed to transfer 630 KJ of heat energy.

Finally, we shall determine the mass of C₆H₆ that will decompose to transfer 430 KJ of heat energy.

From the balanced equation above,

78 g of C₆H₆ decomposed to transfer 630 KJ of heat energy.

Therefore,

X g of C₆H₆ will decompose to transfer 430 KJ of heat energy i.e

X g of C₆H₆ =

Thus, 53.24 g of C₆H₆ will decompose to transfer 430 KJ of heat energy

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it would be b. 6co2 + 6h2o --> c6h12o6 + 6o2