The heat released when the temperature of 25 grams of water changes from 75 c to 30 c

Q = -4702.5 J

Explanation:

Given data:

Mass of water = 25 g

Initial temperature = 75°C

Final temperature = 30°C

Heat released = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT  = T2 - T1

ΔT  = 30°C - 75°C

ΔT  = -45°C

Q = m.c. ΔT

Q = 25 g× 4.18 J/g.°C × -45 °C

Q = -4702.5 J

a c d and f

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