for the uncatalyzed reaction is 14.0 kj. for the same reaction when catalyzed is11.9 kj. what is the ratio of the rate constant for the catalyzed reaction to that for the uncatalyzed reaction at 89ºc? assume the frequency factor is the same for each reaction. ratio =

The ratio is 2:1

Explanation:

The relation between activation energy, temperature and reaction constant is formulated as Arrhenius equation, which is:

Where

K = rate constant

A= frequency factor

T= temperature (K)

R= gas constant

Here A and R both are constant for the two given conditions

So

Equating the two

)=\frac{14000}{8.314X362}-\frac{11900}{8.314X362}=0.698" alt="\frac{K_{cat}}{K_{uncat}}=2" />)=\frac{14000}{8.314X362}-\frac{11900}{8.314X362}=0.698" />

Taking antilog

question: ray weighs 100 kilograms, his wrestling partner, bobby, weighs 50 kilograms. if ray moves at 4 m s , how fast will bobby have to run at him to apply an equal amount of kinetic energy?

answer: 8 m/s he needs to run twice as fast to keep up so he has some work to do

explanation:   if the mass has units of kilograms and the velocity of meters per second, the kinetic energy has units of kilograms-meters squared per second squared.

question answered by

(jacemorris04)

all eukaryotic cell have mitochondria : )