Calculate the change in entropy of the system when 10g of ice at -10c is converted into water vapor at 115c and at a constant pressure of 1bar. the constant pressure molar heat capacity of h2o(s) and h2o(l) is 75.291j/kmol and that of h2o(g) is 33.58j/kmo

Total change in entropy of the system is 85.84 J/K

Explanation:

Δ = Δ+Δ+Δ+Δ

Δ = total entropy of the system in J/K

Δ = entropy due to warming ice from - 10°C (263 K) to 0°C (273 K) in J/K

Δ = entropy due to melting of ice at 0°C (273 K) in J/K

Δ = entropy due to warming liquid from 0°C (273 K) to 115°C (388 K) in J/K

Δ = entropy due to vaporizing liquid at 115°C (388 K) in J/K

Therefore,

Δ = m**

m = mass = 10 g;   = specific heat of ice = 2.106 J/(g*K)

Δ = 10*2.106* = 0.79 J/K

Δ = m*/273

m = 10 g; = 334 J/g

Δ = 10*334/273 = 12.23 J/K

Δ = m**

m = mass = 10 g;   = specific heat of water = 4.218 J/(g*K)

Δ = 10*4.218* = 14.83 J/K

Δ = m*/388

m = 10 g; = 2250 J/g

Δ = 10*2250/388 = 57.99 J/K

Therefore,

Δ = Δ+Δ+Δ+Δ = 0.79+12.23+14.83+57.99 = 85.84 J/K

Thus, the change in entropy of the system is 85.84 J/K

explanation:

venn diagram is pictorial representation with of circles showing the relation between two finite sets or things. the intersection part of two circles conveys the relation present in between those sets or things.

here in the venn diagram of sand and salt two circles represent sand and salt. but the area falling under the intersection of these circle represents the mixture of sand and salt.

so, in a venn diagram the mixture will be placed in a middle that is in between the intersection of two circles.