Consider this equilibrium reaction at 400 k. br2(g)+cl2(g)↽−−⇀2brcl(g)kc=7.0 br 2 ( g ) + cl 2 ( g ) ↽ − − ⇀ 2 brcl ( g ) k c = 7.0 if the composition of the reaction mixture at 400 k is [brcl]=0.004150 [ brcl ] = 0.004150 m, [br2]=0.003660 [ br 2 ] = 0.003660 m, and [cl2]=0.0006720 [ cl 2 ] = 0.0006720 m, what is the reaction quotient, q ?

The reaction quotient is:- 7.00238

Explanation:

The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.

It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.

The equation is as follows:-

The expression for the reaction quotient is:-

Given,

So,

The reaction quotient is:- 7.00238

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2