Using resonance, select the most acidic protons in the hexane-2,4-dione molecule. the most acidic proton is the one that, upon removal, will yield the most stable conjugate base.
check all that apply.
[hexane-2,4-dione molecule with protons numbered as follows according to iupac nomenclature: protons on c1 are numbered 1 through 3, protons on c3 are numbered 4 and 5, protons on c5 are numbered 6 and 7, protons on c6 are numbered 8 through 10.]

check all that apply.

protons 1, 2, or 3
protons 4 or 5
protons 6 or 7
protons 8, 9, or 10

Protons 4 or 5 are most acidic.

Explanation:

As mentioned there are four types of hydrogen in Hexane-2,4-dione.

The numbering are shown in the figure for your better understanding.

As shown in the figure if we remove the proton from carbon number 3 (protons number 4 or 5), it will result in formation of a carbanion. This carbanion is stabilized due to presence of -I group oxygen and there is possibility of resonance (as shown).

Thus protons 4 or 5 are most acidic.

screening

explanation:

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles