If 5.0 liters of carbon dioxide gas are produced by the reaction below at 273 k and 1.00 atm, how many liters of oxygen gas were used in the reaction?

The balanced chemical reaction was not given. I will just assume an organic compound for this case. The balanced reaction would be:

C6H6 + 15/2O2 = 6CO2 + 3H2O

We are given the amount of carbon dioxide gas produced from the reaction. This will be the starting point of our calculation. We use the ideal gas equation to find for the number of moles.

n = PV / RT = 1.00(5L) / (0.08206 atm L/mol K ) 273 K
n= 0.2232 mol CO2

0.2232 mol CO2 (15/2 mol O2 / 6 mol CO2) ( 14.03 g CO2 / 1 mol CO2 ) = 3.9144 mol O2

V = nRT/P = 3.9144 mol O2 x 273 K x 0.08206 atm L/mol K / 1 atm
V=87.6912 L

assuming that your periodic table has eighteen columns, you should highlight   the four elements in the third column from the left of the table.

explanation

neutral atoms of elements after calcium contain d electrons. the energy of d orbitals of a particular main shell lies between the energy of the s and p orbitals of the next main shell. for example, electrons in the have energy higher than those in the orbital while lower than those of the orbital.

by the aufbau principle, electrons fill orbitals one at a time, starting from those of the lowest energy. the orbital is therefore filled right after orbitals and before orbitals.  

potassium has electron configuration and calcium . the s orbital of a main shell holds a maximum of two electrons. the next element would thus have the electron configuration and satisfy the requirements.

a neutral atom of the element contains three electrons on top of the most recent noble gas element. it should thus be placed in the third column of the periodic table. both scandium and yttrium would satisfy the conditions. an aufbau diagram indicates that the 4f orbital is filled before the 5d. however, it appears that exceptions exists for both lanthanum and actinium. neutral atoms of the two d-block elements also demonstrate the and should be highlighted as well.

Is there an image with it