If 0.771 g of o3 reacts with 0.663 g of no, how many grams of no2 will be produced?

Mass = 0.92 g

Explanation:

Given data:

Mass of O₃ = 0.771 G

Mass of NO₂ = 0.663 g

Mass of NO₂ produced = ?

Solution:

Chemical equation:

O₃ + NO → NO₂ + O₂

Number of moles of O₃ :

Number of moles = mass/ molar mass

Number of moles = 0.771 g/ 48 g/mol

Number of moles = 0.02 mol

Number of moles of NO:

Number of moles = mass/ molar mass

Number of moles = 0.663 g/ 30 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of NO₂ with NO and O₃ .

                NO       :        NO₂

                 1           :         1

              0.02        :      0.02

                O₃          ;        NO₂

                1             :         1

            0.02          :         0.02

Mass of NO₂:

Mass = number of moles × molar mass

Mass = 0.02 mol × 46 g/mol

Mass = 0.92 g

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.