Pentane is a small liquid hydrocarbon, between propane and gasoline in size at c5h12. the density of pentane is 0.626 g/ml and its enthalpy of combustion is δh°comb = –3535 kj/mol. estimate the fuel value and the fuel density of

Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and   respectively.

Explanation :

Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).

As we are given that:

Fuel value =

Molar mass of pentane = 72 g/mol

Fuel value =

Fuel value = 49.09 kJ/g

Now we have to calculate the fuel density of pentane.

Fuel density = Fuel value × Density

Fuel density = (49.09 kJ/g) × (0.626g/mL)

Fuel density = 30.73 kJ/mL =

Thus, the fuel density of pentane is

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.