The product of a reaction between pentyl propanoate and water in the presence of an acid is view available hint(s) the product of a reaction between pentyl propanoate and water in the presence of an acid is sodium propanoic acid and pentanol pentyl propanoic acid and water pentanol and propanoic acid propanol and pentanoic acid g

Pentanol and propanoic acid

Explanation:

Alkanoates ( esters ) are condensation products of the reversible reaction between an alkanol and an alkanoic acid in the presence of a mineral acid which acts as a catalyst.

Alkanol + Alkanoic acid = Alkanoate(ester) + water

ROH + RCOOH = RCOOR + H2O

E.g

Ethanol + Ethanoic acid = Ethylethanoate + water

C2H5OH + CH3COOH = CH3COOC2H5 + H2O

The forward reaction is called esterification while the reverse reaction is called acid hydrolysis.

In naming esters, the end alkyl, R, from the alkanol is named first as alkyl before the RCOO- is then named by replacing the -oic acid with -oate.

E.g CH3COOCH3 is methylethanoate.

C2H5COOCH3 is methylpropanoate.

Esters undergo acid hydrolysis (the acid acts as the catalyst) in the presence of water to yield the alkanols and alkanoic acids that formed them.

E.g

ethylethanoate + water = ethanol + ethanoic acid.

Note that the ethanol is from the ethyl and ethanoic acid from the ethanoate.

For the above question:

Pentylpropanoate + water = pentanol + propanoic acid

C2H5COOC5H11 + H2O = C5H11OH + C2H5COOH