Compounds x and y are both c7h15cl products formed in the radical chlorination of 2,4-dimethylpentane. base-promoted e2 elimination of x and y gives, in each case, a single c7h14 alkene. both x and y undergo an sn2 reaction with sodium iodide in acetone solution to give c7h15i products; in this reaction y reacts faster than x. what is the structure of x?

X  is 3-chloro-2,4-dimethylpentane

Explanation:

The radical chlorination of 2,4-dimethylpentane may give three products.

Based on the information that

i) both the products gives single alkene on elimination and

ii) both the products also undergoes SN2 reaction but Y reacts faster than X

We may conclude that as SN2 reaction is faster in primary alkyl halides as compared to secondary or tertiary so Y must be primary or secondary and it cannot be tertiary alkyl halide.

The possible products are shown in the figure.

The structure of X is shown in the figure.

i think its 5049.

i hope this !

explanation: