In a 108.40 g empty beaker, 2.70 g of sodium reacts with an excess solution of iron ( iii ) acetate . after the reaction, the liquid is poured off and only the iron remains in the beaker and is left out overnight to dry. the next day the iron and the dry beaker have a mass of 110.28g. a calculate the theoretical yield of the iron produced a b calculate the percent yield of iron c if the percent yield is actually 93.1% , how much iron would have formed?