Argon and methane are absorbed from nitrogen into liquid ammonia at 2523 k and 175.0 atm. feed rate of gas is 100.0 kmol/h. feed gas contains 0.020 mol% ar and 0.130 mol% methane. outlet gas contains 0.0008 mol% methane. entering liqud ammonia is pure. operate with l/v-26.0. assume l and v flow rates are constam equilibrium data for methane is, partial pressure methane = 3600 atm and the partial pressure for argon = 7700 atm
a. find the outlet mole fraction of methane in the liquid
b. find the number of equilibrium stages required.
c. find the outlet mole fraction of argon in the gas.

It will fall off and tip over. 

The disturbance is only parallel to the motion of the wave.

The ground state electron configuration of a phosphorous atom has  three unpaired electrons. they're in the 3p sublevel. the electron configuration is: , for a total of  15 electrons.

Use the universal gas law formula: pv = nrt now, the key word in this problem is stp, so at stp, temperature will always be 0 degrees celsius and pressure will always be 1.0 atm or 760 torr. given something is at stp, we already know the two variables pressure and temperature. the other thing we can find with the given information is moles. to find moles, just divide grams by molar mass of the element. 16.0g / 2(16.00)g/mol = 0.5 moles plug the values in to the equation pv = nrt (1.0 atm)( x ) = (0.5 )(0+273=273k) the r value is just a constant for when we use atm, liters, moles and kelvin. i'm assuming you want your answer in liters, but if you dont just move the decimal 3 to the right in your final answer. so when plugging these numbers in to your calculator and trying to find x, you get 11.20665 liters using significant figures the answer is 11.2 liters