If a chemist wants to make 1.3l of 0.25m solution of koh by diluting a stock solution of 0.675 m koh, how many milliliters of the stock solution would the chemist need to use?

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

.675 M x V1 = .25 M x 1.3 L

V1 = 0.48 L or 480 mL

d. temperate deciduous forest

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.