A25.0 ml sample of h3po4 requires 50.0 ml of 1.50 m naoh for complete neutralization. what is the molarity of the acid?

The molarity of acid is 3 M.

Explanation:

Given data:

Volume of H₃PO₄ = 25 mL

Volume of NaOH = 50 mL

Molarity of NaOH = 1.50 M

Molarity of  H₃PO₄ = ?

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = M₂V₂ / V₁

M₁ = 1.50 M ×50 mL / 25 mL

M₁ = 75 M. mL / 25 mL

M₁ = 3 M

The molarity of acid is 3 M.

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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