Imagine two solutions with the same concentration and the same boiling point, but one has benzene as the solvent and the other has carbon tetrachloride as the solvent. determine that molal concentration, m (or b), and boiling point, tb.

benzene boiling point=80.1 kb=2.53

carbon tetrachloride boiling point=76.8 kb=5.03

Concentration = 1.32 m

Boiling point =

Explanation:

Let the boiling point of two solutions = T

Let the molal concentration of the two solutions= m

The relation between elevation in boiling point and molal concentration is:

i) For benzene

....(1)

ii) For carbon tetrachloride

...(2)

Equating the two equations:

Putting value of "m" in equation "1"

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

each  column  of the  table  is called a group. elements in a group share similar properties. groups are  read  from  top  to  bottom. metal. metalloid. nonmetal. solid. liquid. gas. fe. hg. o.  2. 3. 4. 5. 6. 7. 8. 9.  2. beryllium. 9.012. 4.  sodium. 22.990.  11. 3.  magnesium. 24.305.  12.  potassium. 39.098.  19. 4.  calcium. 40.078.  20. i guess  i