The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.0 x 10-5 s-1 at 10 km above the planet’s surface. consider a laboratory experiment in which a vessel of ozone is exposed to uv radiation at an intensity chosen to mimic the conditions at that altitude. if the initial o3 concentration is 5.0 x 10-3m, what will the concentration be after 10.0 day?

[O₃]= 8.84x10⁻⁷M  

Explanation:

The photodissociation of ozone by UV light is given by:

O₃ + hν → O₂ + O (1)

The first-order reaction of the equation (1) is:

(2)

where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration    

We can get the following expression of the first-order integrated law of the reaction (1), by resolving the equation (2):

(3)

where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration

We can calculate the initial ozone concentration using equation (3):  

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

we can conclude that the melting point of table salt is above room temperature (it's actually 801 deg c). the melting point of mercury must be below room temperature (- 39 deg c).

no podemos ver la

explanation:

no te podemos ayudar: /