Apiston system absorbs 50.5 j of energy in the form of heat from the surroundings. the piston is working against a pressure of 0.491 atm. the final volume of the system is 56.2 l. what was the initial volume of the system if the internal energy of the system decreased by 106.0 j? (to convert between l∙atm and j, use 1 l∙atm = 101.3 j.)

The initial volume of the system: V₁ = 53.06 L

Explanation:

Given: heat absorbed by system: q =  50.5 J, Pressure: P = 0.491 atm, Final volume: V₂ = 56.2 L, The change in the internal energy: ΔE = -106.0 J

Initial volume: V₁ = ? L

According to the First Law of Thermodynamics:

ΔE = q - PΔV

⇒ PΔV = q - ΔE = 50.5 J - (-106.0 J) = 156.5 J

As, 1 L∙atm = 101.3 J  ⇒   1 J = (1 ÷ 101.3) L∙atm

⇒ PΔV = 156.5 J = (156.5 ÷ 101.3) L∙atm = 1.54 L∙atm

So,

ΔV = 1.54 L∙atm ÷ P = 1.54 L∙atm ÷ 0.491 atm = 3.14 L

∵ ΔV = V₂ - V₁ = 3.14 L

⇒ V₁ = V₂ -  3.14 L = 56.2 L -  3.14 L = 53.06 L

Therefore, the initial volume of the system: V₁ = 53.06 L

why is cellular respiration important for homeostasis?

it changes food into energy that the organism can use.

which of the following is most likely to happen if a cell is not able to divide?

the cell will not be replaced when it is damaged.

explanation:

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.