Consider the following neutral electron configurations in which n has a constant value. which configuration would belong to the element with the most negative electron affinity, eea? view available hint(s) consider the following neutral electron configurations in which n has a constant value. which configuration would belong to the element with the most negative electron affinity, a. 5s2 b. 5s25p2 c. 5s25p5 d. 5s25p6

"c" is the element with the most negative electron affinity.

Explanation:

We can obtain the following information from the electron configuration:

Period: Is the level in which the differential electron is in.

Group: Is the sum of all electrons in the last level.

Knowing their ubication in the periodic table, we can classify them as metals, nonmetals or noble gases.

a. 5s²            P: 5    G: IIA (2) Metal

b. 5s²5p²      P: 5    G: 2 + 2 = IVA (14) Nonmetal

c. 5s²5p⁵      P: 5    G: 2 + 5 = VIIA (17) Nonmetal

d. 5s²5p⁶      P: 5    G: 2 + 6 = VIIIA (18) Noble gas

Noble metals have a low tendency to gain electrons so their electron affinity is neglectable. For elements in the same period, the electron affinity gets more negative from left to right. Therefore, "c" is the element with the most negative electron affinity.

answer: lol

explanation:

lol

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g