Without doing a calculation, predict whether your estimate in part (a) is more negative or less negative than the true reaction enthalpy. without doing a calculation, predict whether your estimate in part (a) is more negative or less negative than the true reaction enthalpy.

a. the estimate from part a is less positive or smaller than the true reaction enthalpy.

b. the estimate from part a is less positive or larger than the true reaction enthalpy

c. the estimate from part a is equal to the true reaction enthalpy

d. the estimate from part a is less negative or larger than the true reaction enthalpy.

i need mutiple choices

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence