Oxalic acid reacts with sodium hydroxide according to the following equation:
h2c2o4 + 2 naoh → na2c20. + 2 h20
a 25.00 ml sample of the h2c2o solution required 19.62 ml of 0.341 m naoh for
neutralization. calculate the molarity of the acid.

Concentration = 0.14 M

Explanation:

Given data:

Volume of base = 19.62 mL

Molarity of base = 0.341 M

Volume of acid = 25.00 mL

Molarity of acids = ?

Solution:

Number of moles of base = Molarity × volume in litter

Number of moles = 0.341 mol/L × 0.02 L

Number of moles =  0.007 mol

Concentration of acid:

Concentration = 1/2 (0.007 mol) / 25 mL × 10⁻³ L/mL

Concentration = 0.0035 mol / 25 × 10⁻³ L

Concentration = 1.4  × 10⁻¹ M

Concentration = 0.14 M

14,16 18 reacts with group

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