Dinitrogen oxygen, n2o, has two double bonds. the general structure is n=n=o. the formal charge on the oxygen atom isa.) 0b.) +1c.) +2d.) -1

A.) 0

Explanation:

Dinitrogen oxygen ()

Valence electrons of oxygen = 6

Valence electron of nitrogen = 5

The total number of the valence electrons  = 2(5) + 6 = 16

The Lewis structure is drawn in such a way that the octet of each atom and duet for the hydrogen in the molecule is complete. So, The Lewis structure is shown in image below.

Formula for formal charge :

Formal charge for oxygen:

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2

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