For which of the following equations is the change in enthalpy at 25 celcius and 1 atm pressure equal to δhf of ch3oh (l)? a.) ch3oh + 3/2 o2 > co2 + 2h2o (l)b.) ch3oh + 3/2 o2 > co2 + 2h2o (g)c.) 2ch3oh + 3o2 > 2co2 + 4h2o (l)d.) c + 2h2 + 1/2 o2 > ch3oh

D. C + 2H₂ + ¹/₂O₂ → CH₃OH

Explanation:

The standard enthalpy of formation -ΔHf- is defined as the enthalpy change for the formation of 1 mol of a compound from its component elements.

Component elements are any element in its standard state.

For CH₃OH(l) at 25°C and 1 atm of pressure, the component elements are C(s), H₂(g) and O₂(g)

Thus, the equation that represent the standard enthalpy of formation of CH₃OH(l) is:

D. C + 2H₂ + ¹/₂O₂ → CH₃OH

I hope it helps!

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