The rate law for a hypothetical reaction is rate = k [a]2. when the concentration is 0.10 moles/liter, the rate is 2.7 × 10-5 m*s-1. what is the value of k?

Given:

rate = k [A]2

concentration is 0.10 moles/liter

rate is 2.7 × 10-5 M*s-1

Required:

Value of k

Solution:

rate = k [A]2

2.7 × 10-5 M*s-1 = k (0.10 moles/liter)^2

k = 2.7 x 10^-3 liter per mole per second

the answer would be b i believe

< > according to newton's third law of motion, forces always act in equal but opposite pairs. another way of saying this is for every action, there is an equal but opposite reaction.< >