How many moles of iron (ii) iodine are produced when 112 grams of iron (ii) reacts with excess iodine?

2moles

Explanation:

The best way to solve this problem is to write a balance equation for the reaction.

Which is: Fe2 + 2i2> 2Fei2

With this you can see that iron ii reacting with excess iodine produces two (2) moles of iron ii iodine.

Alternatively.

Using the formular

Moles = reacting mass/molar mass

Reacting mass = 112g

Molar mass of iron ii = 55g/mol

Hence,

Mole = 112g divides 55g/mol

= 2.0mol//

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.