0.214 mol agno3 and 3.58 mol nh3 were added to enough water to give 1.00 l of solution at 25 °c. calculate the equilibrium concentration of free silver ion , [ag+], in this solution. the formation constant for ag(nh3)2+ (kf) = 1.50 x 10^7 at 25 °c.

the answer is na (sodium)

c

explanation:

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.