Balance the following oxidation-reduction reaction and indicate which atoms have undergone oxidation and reduction. + > +

Explanation:

An equation that contains equal number of atoms on both reactant and product side is known as a balanced chemical equation.

Whereas when there will be increase in oxidation number of the atom then it is known as oxidation. When there is decrease in oxidation number of the atom then it is known as reduction.

For example,

Oxidation half reaction :

Reduction half reaction :

Therefore, we can conclude that sulfur atom has undergone oxidation and nitrogen atom has undergone reduction.

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the answer would be a