Avinegar solution of unknown concentration was prepared by diluting 10.00ml of vinegar to a total volume of 50.00ml with deionized water.
a 25.00 ml sample of a diluted vinegar solution required 20.78 ml of 0.1032 m naoh to reach the titration equivalence point.

calculate the concentration of acetic acid (ch3cooh) in the original vinegar solution (before dilution).a. 4.289 x 10^-4 mb. 2.144 x 10^-3mc. 8.578 x 10^-1md. 4.289 x 10^01m

the grams   of   barium that   are in   2.3 x 10^23   atoms of barium   is   52.4 g (answer c)

    calculation

mass = moles   of ba   x molar   mass of ba

  molar mass of ba from periodic table=   137.3 g/mol

  use the   avogadro's law   constant   to   calculate the moles of barium

  that   is     1 mole =   6.02   x 10^23 atoms

                    ? moles = 2.3 x 10^23   atoms

by cross   multiplication

=(1 mole   x 2.3x 10^23 atoms)   / 6.02   x10^23 atoms)=   0.382   moles

mass   is therefore = 137.3   g/mol x 0.382 mol = 52.4 ( answer c)

explanation: