If 25 ml of koh were needed to neutralize 15 ml of 3.5 m hbr, calculate the molarity of the base

2.1 M KOH is required.

Explanation:

It is an example of acid-base neutralization reaction.

KOH  +  HBr  ---->  KBr  +  

Base     Acid           Salt        

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity=

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

------------------------------(1)

where

= Molarity of Acid

= Volume of Acid

= Molarity of Base

= Volume of Base

=3.5 M

=15 mL

=25 mL

=??(in M)

Plugging in Equation 1,

3.5 × 15 = × 25

=

=2.1 M

personal, she chose to do it.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o