Treating 2-methyl-1-butene with methanol in the presence of sulfuric acid gives 2-methoxy-2-methylbutane. draw curved arrows to show the movement of electrons in this step of the reaction mechanism.

Reaction proceeds in three steps- protonation, nucleophilic addition and deprotonation

Explanation:

Reaction of 2-methyl-1-butene with methanol in the presence of sulfuric acid proceeds through a carbocationic intermediate.In the first step, protonation of double bond in 2-methyl-1-butene occurs to produce a stable tertiary carbocation.In the second step, nucleophilic addition of methanol occurs into the carbocation.In the third step, deprotonation from -OH group of methanol occurs to produce 2-methoxy-2-methylbutane.Reaction mechanism is shown below.

Ans(15) minutes;