Assume the molality of isoborneol in your product is 0.275 mol/kg. what is the melting point of your impure sample given that the melting point of pure camphor is 179°c and its freezing point depression constant is 40°c·kg/mol?

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = = ?

Depression in freezing point =

Depression in freezing point  is also given by formula:

= The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: = 40°C kg/mol

i = 1 (  non electrolyte)

168°C is the melting point of your impure sample.

the answer your looking for is c).

answer is: nuclear fusion produces elements that are heavier than helium.

nuclei combine to form a heavier nucleus, releasing energy.  

for example, fusion of hydrogen atoms at the sun.  

this fusion nuclear reaction is in the inner core of the sun and hydrogen (atomic number 1) is conveted into helium (atomic number 2).  

the inner core is the central region of the sun and all solar energy is produced in the core by nuclear fusion.