write the nuclear equation for the alpha decay of:
(a) ra-256

(b) rn - 219

(c) po - 211

(d) pb-210

(e) u-238

The answer to your question is below

Explanation:

Alpha decay occurs when a radioactive atm emits an alpha particle (Helium atom).

a)      ²⁵⁶Ra      ⇒      ²⁵²₈₄ Po  +   ⁴₂He

b)     ²¹⁹Rn       ⇒      ²¹⁵₈₂Pb    +   ⁴₂He

c)      ²¹¹Po      ⇒      ²⁰⁷₈₀Hg    +   ⁴₂Hg

d)      ²¹⁰Pb     ⇒     ²⁰⁶₇₈Pt      +   ⁴₂Hg

e)      ²³⁸U      ⇒     ²³⁴₈₈U       +   ⁴₂Hg

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

i need mutiple choices