Usted desea determinar el contenido de cobre que se pueda precipitar a partir a partir de 4 metodos diferentes. en el primer metodo se precipita sulfato de cobre(cuso4), obteniendos 151g. en el segundo metodo se precipita hidroxido de cobre(cu(oh)2), obteniendose 110g. en el tercer metodo se precipita cloruro de cobre (cucl2), obteniendo210g. finalmente en el cuarto metodo se precipita nitrato de cobre(cu(no3)2), obteniendose 251g. calcule el factor gravimetrico del cobre en cada metodo

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.

i believe the answer is 5,000

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.