How long would it take to reduce 1 mole of each of the following ions using the current indicated? assume the voltage is sufficient to perform the reduction. (a) al3+, 1.234 a (b) ca2+, 22.2 a (c) cr5+, 37.45 a (d) au3+, 3.57 a

Explanation:

(a)     It is given that for value of current is 1.234 A.

Hence, total charge Q =

                                     = 289455 C

Now, we will calculate the time as follows.

                      t =

                        =

                        = 234566.4506 s

or,                    =                    

                       = 65.16 hr

(b)    It is given that for , value of current is 22.2 A.

Hence, its total charge Q =

                                         = 192970 C

Now, we will calculate the time  as follows.

                            t =

                              =

                              = 8692.34 s

or,                          = 2.4 hr

(c)   It is given that for , value of current is 37.45 A.

Hence, the total charge Q =

                                        = 482425 C

Now, we will calculate the time  as follows.

                      t = \frac{Q}{I}[/tex]

                        = \frac{482425 C}{37.45 C/s}[/tex]

                       = 12881.8 s

or,                    = 3.6 hr  

(d)    It is given that for , value of current is 3.57 A.

Hence, the total charge Q =

                                          = 289455 C

Now, we will calculate the time as follows.

                      t =

                        =

                       = 81079.83 s

                       = 22.5 hr

idk what the question is about