Asample of sulfur dioxide occupies a volume of 562 ml at 45.° c and

720 kpa. what volume will the sulfur dioxide occupy at stp?

3.43 L

Explanation:

By the ideal gas law, when there is a state change, the quantities can be calculated by:

P1*V1/T1 = P2*V2/T2

Where P is the pressure, V is the volume, T is the temperature in K, 1 is the initial state, and 2 the final state.

P1 = 720 kPa, V1 = 562 mL, T1 = 45°C + 273 = 318 K

STP: P = 1 atm = 101.325 kPa, T = 273 K

720*562/318 = 101.325*V2/273

0.371153846V2 = 1272.45283

V2 = 3428 mL = 3.43 L

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