calcium carbonate decomposes at 1200.0°c and forms carbon dioxide and calcium oxide. if 33.0 l of carbon
dioxide is collected at 1200.0° c and is then cooled to 30 °c, what is the new volume of carbon dioxide gas?

Explanation:

The pressure is constant, so, to calculate the volume, we can use Charles' Law.

Data:

V₁ = 3300 L; T₁ = 1200.0 °C

V₂ = ?;          T₂ =     30    °C

Calculations:

(a) Convert temperatures to kelvins

T₁ = (1200.0 + 273.15) K = 1473.15 K

T₂ =    (30    + 273.15) K =  303.15 K

(b) Calculate the new volume

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%