The distribution of na+ ions across a typical biological membrane is 10 mmol dm-3 inside the cell and 140 mmol dm-3 outside the cell. at equilibrium the concentrations are equal. what is the gibbs energy difference across the membrane at 37oc in units of kj mol-1?

Answer :  The value of across the membrane is 6.80 kJ/mol

Explanation :

The relation between the equilibrium constant and standard Gibbs free energy is:

where,

= standard Gibbs free energy  = ?

R = gas constant = 8.314 J/K.mol

T = temperature =

 = equilibrium constant

= concentration inside the cell =

= concentration outside the cell =

Now put all the given values in the above formula, we get:

Thus, the value of across the membrane is 6.80 kJ/mol