If the theoretical yield of the reaction below corresponds to 25.3 g and the percent yield of the reaction is known to be reproducibly 81.1%, calculate the actual yield. given: li2o + h2o → 2 lioh

Actual yield = 20.52 g

Explanation:

Given data:

Theoretical yield = 25.3 g

Percentage yield = 81.1 %

Actual yield = ?

Solution:

Formula:

Percentage yield = Actual yield /theoretical yield × 100

81.1 % /100 = Actual yield / 25.3 g

0.811 = Actual yield / 25.3 g

Actual yield = 0.811 × 25.3 g

Actual yield = 20.52 g

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