40.0 g neon and 40.0 g helium has a total pressure of 0.900 atm, what is the the partial pressure of the neon?

P₁ = 0.18 atm

Explanation:

Given data:

Mass of neon = 40 g

Mass of helium = 40 g

Total pressure = 0.90 atm

Partial pressure of neon = ?

Solution:

Number of moles of helium

Number of moles of helium = mass/ molar mass

Number of moles of helium = 40 g/ 4 g/mol

Number of moles of helium = 10 mol

Number of moles of neon:

Number of moles of neon = mass/ molar mass

Number of moles of neon = 40 g/ 20g/mol

Number of moles of neon = 2 mol

Partial Pressure of neon:

P₁ = [ n₁ / nt ] × Pt

P₁ = partial pressure of neon

n₁ = 2 mol

nt = 10 mol + 2 mol = 12 mol

P₁ =  [ 2 mol /  12 mol ]× 0.900 atm

P₁ = 0.2× 0.900 atm

P₁ = 0.18 atm

can you attach the

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.