What is the most likely ion for magnesium to become when it is ionized?

Atoms want to be stable, that's essentially their only purpose in life.

How, then, does an atom become stable? Well, they either lose all their electrons, or gain electrons so they have 8 (Except for a couple atoms like helium, they just need two electrons).

Magnesium has two valence electrons, and obviously it seems a bit unconventional to try and gain 6 electrons when you could just lose 2. Why spend more effort?

Because it loses 2 electrons, Mg will become (It has lost 2 electrons, and therefore becomes positive)

Good luck! If you have any questions, just ask :))

-T.B.

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.