The amount of calcium present in milk can be determined through gravimetric analysis by adding oxalate to a sample and measuring the mass of calcium oxalate precipitated. what is the mass percent of calcium in milk if 0.429 g of calcium oxalate, cac2o4, forms in a 125-g sample of milk when excess aqueous sodium oxalate is added? na2c2o4 (aq) + ca2+ (aq) → cac2o4 (s) + 2 na+ (aq)

The mass percent of calcium in milk is 0.106 %

Explanation:

To calculate the number of moles, we use the equation:

     .....(1)

Given mass of calcium oxalate = 0.429 g

Molar mass of calcium oxalate = 128.1 g/mol

Putting values in equation 1, we get:

The given chemical equation follows:

Sodium oxalate is present in excess. So, it is considered as an excess reagent. And, calcium ion is a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of calcium oxalate is produced from 1 mole of calcium ion.

So, 0.0033 moles of calcium oxalate is produced from = of calcium ions

Now, calculating the mass of calcium ions by using equation 1, we get:

Moles of calcium ions = 0.0033 moles

Molar mass of calcium ions = 40 g/mol

Putting values in equation 1, we get:

To calculate the mass percentage of calcium ions in milk, we use the equation:

Mass of milk = 125 g

Mass of calcium ions = 0.132 g

Putting values in above equation, we get:

Hence, the mass percent of calcium in milk is 0.106 %

i think that the answer is c