Avolleyball player hit a ball with a mass of 0.25 kg. the average acceleration of the ball is 15.5 m/s². how much force did the volleyball player apply to the ball? 3.87 m/s² 3.87 n 62.0 m/s² 62.0 n

F = 3.87 N

Explanation:

Given data:

Mass = 0.25 Kg

Acceleration = 15.5 m/s²

Force = ?

Solution:

Formula:

F = m × a

F =  0.25 Kg×15.5 m/s²

F = 3.87  Kg.m/s²

Kg.m/s² = N

F = 3.87 N

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

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