Aspherical glass container of unknown volume contains he-
lium gas at 25°c and 1.960 atm. when a portion of the helium
is withdrawn and adjusted to 1.00 atm at 25°c, it is found to
have a volume of 1.75 cm3. the gas remaining in the first con-
tainer shows a pressure of 1.710 atm. calculate the volume of
the spherical container.

The volume of the spherical container is 7 cm³ (= 7 mL)

Explanation:

Step 1: Data given

Temperature = 25°C

Pressure = 1.960 atm

Adjusted pressure = 1.00 atm

Volume = 1.75 cm³ ( = 1.75 mL)

The gas remaining in the first container shows a pressure of 1.710 atm

Step 2: Boyle's law

p*V = p*V

(1.960atm - 1.710 atm)*V = (1atm * 1.75 cm³)

0.250 atm * V = 1atm * 1.75 cm³

V = (1 atm * 1.75 cm³)/ 0.250 atm

V = 7 cm³ = 7 mL

The volume of the spherical container is 7 cm³ (= 7 mL)

the product of the pressure and volume is also constant