Achemist prepares a solution of calcium sulfate (caso_4) by measuring out 0.0101 g of calcium sulfate into a 350. ml volumetric flask and filling the flask to the mark with water. calculate the concentration in mol/l of the chemist's calcium sulfate solution. round your answer to 3 significant digits.

2.123x10⁻⁴ M (mol/L)

Explanation:

First, we are considering the molar mass for each element, a data we obtain from the periodic table:

Ca= 40

S= 32

O= 16

Then, for CaSO₄, the molecular mass is 136 g per mol

As we dissolve 0.00101 g of this salt, we are going to convert this mass in moles units:

1 mol CaSO₄=136 g → 0.0101 g=7.43x10⁻⁵ mol

We finally obtain the concentration for the 350 ml, having in mind that it should be in mol/L:

350ml=7.43x10⁻⁵ mol

1000ml (1L)=2.123x10⁻⁴ M , where M=mol/L

c.

explanation:

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.